极乐门资源网

基于jQuery判断两个元素是否有重叠部分的代码
网络编程 2025/1/22 佚名
2 0
极乐门资源网 Design By www.ioogu.com
核心代码：
复制代码 代码如下:
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}

原理很简单，就是判断一个元素的四个点是否在另一个元素内部。
完整演示代码：
复制代码 代码如下:
JSCode
LoginResult JavaScript HTML CSS ALL Edit Share
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<h1 id="result"></h1>
div{
width:200px;
height:200px;
background:#EEE;
}
#two{
position:absolute;
left:100px;
top:50px;
background:#F60;
}
DownLoad
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8"/>
<title>JSCode demo</title>
<style type="text/css">
div{
width:200px;
height:200px;
background:#EEE;
}
#two{
position:absolute;
left:100px;
top:50px;
background:#F60;
}
</style>
<script src="/UploadFiles/2021-04-02/jQuery-1.7.2.js"></head>
<body>
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<h1 id="result"></h1>
<script type="text/javascript">
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
</script>
</body>
</html>
Share link
Embed on your page
Share on Sina
Share on QQ

作者：Artwl
标签：
元素,重叠
极乐门资源网 Design By www.ioogu.com
极乐门资源网 免责声明：本站文章均来自网站采集或用户投稿，网站不提供任何软件下载或自行开发的软件！ 如有用户或公司发现本站内容信息存在侵权行为，请邮件告知！ 858582#qq.com
极乐门资源网 Design By www.ioogu.com

评论“基于jQuery判断两个元素是否有重叠部分的代码”

暂无基于jQuery判断两个元素是否有重叠部分的代码的评论...
www.ioogu.com 极乐门资源网
139,976影音资源
144,792福利资源
21,817软件资源
631,128技术资源

更新日志

友情链接

杰晶网络 DDR爱好者之家 桃源资源网 杰网资源 富贵资源网 南强小屋 铁雪资源网 幽灵资源网 万梅资源网 狼山资源网 白云岛资源网 昆仑资源网 相思资源网 明霞山资源网 内蒙古资源网 黑松山资源网 茶园资源网 饿虎岗资源网 大旗谷资源网 常春岛资源网 岱庙资源网 兴国资源网 快活林资源网 蝙蝠岛资源网 帝王谷资源网 白云城资源网 伏龙阁资源网 清风细雨楼 天枫庄资源网 圆月山庄资源网 无争山庄资源网 神水资源网 移花宫资源网 神剑山庄资源网 无为清净楼资源网 金钱帮资源网 丐帮资源网 华山资源网 极乐门资源网 小李飞刀资源网 凤求凰客栈 风云阁资源网 金狮镖局 鸳鸯亭资源网 千金楼资源网 更多链接
极乐门资源网 Design By www.ioogu.com